Status:Closed Asked:May 29, 2012 - 07:15 AM
How do we determine the gsm from Bursting Test?
I have a situation where I need to determine the gsm of a 275# singlewall carton (3 ply). I am guessing that since there are 3 layers in a single wall carton, there will be infinite combination of paper weight to get to an equivalent 275# carton. My question is if I can find out each layers paper weight in gsm, do I add the 3 layers gsm to get the total gsm, and take the total gsm to convert to the bursting test lbs? Is this how it is done?
As you mentioned, there are several "layer" combinations that could be used to create a corrugated board that is rated with a bursting strength of 275 PSI. The bursting strength of a corrugared board, however, can not be derived from it's basis weight. The corrugated would need to be subject to a bursting test in order to find its bursting strength. I recommend you contact the Fibrebox Association for more information. http://www.fibrebox.org/
Source: A.J. Gruber - ISTA
Well, if we are talking within the confines of the mullen version of Rule 41, a 275 single-wall construction requires a minimum combined weight of facings equal to 138 lbs/msf. Assuming a balanced construction, that translates to two 69# liners and a 26# medium. In gsm, that's a 337 (127) 337 construction.
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