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Status:Closed    Asked:May 29, 2012 - 07:15 AM

How do we determine the gsm from Bursting Test?

I have a situation where I need to determine the gsm of a 275# singlewall carton (3 ply). I am guessing that since there are 3 layers in a single wall carton, there will be infinite combination of paper weight to get to an equivalent 275# carton. My question is if I can find out each layers paper weight in gsm, do I add the 3 layers gsm to get the total gsm, and take the total gsm to convert to the bursting test lbs? Is this how it is done?

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As you mentioned, there are several "layer" combinations that could be used to create a corrugated board that is rated with a bursting strength of 275 PSI. The bursting strength of a corrugared board, however, can not be derived from it's basis weight. The corrugated would need to be subject to a bursting test in order to find its bursting strength. I recommend you contact the Fibrebox Association for more information.

Source: A.J. Gruber - ISTA


May 29, 2012 - 07:14 AM

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Well, if we are talking within the confines of the mullen version of Rule 41, a 275 single-wall construction requires a minimum combined weight of facings equal to 138 lbs/msf. Assuming a balanced construction, that translates to two 69# liners and a 26# medium. In gsm, that's a 337 (127) 337 construction.


Jun 22, 2013 - 02:10 PM

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